I want to put a link in android app with userid parameter in link

Here is what I need .... for my mobile chat application to work.......

http://www.ootiz.com/ootiz_chat/m/?userid=XX (where XX is the userid)

www.ootiz.com is my website name

www.ootiz.com/ootiz_chat/m/ is my mobile chat application link

Please anybody help me if you know how to do this in android source code.....

I am able to put the link easily but dont know how to do the userid=XX parameter part

HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!

Please don't post  it multiple times or you will be banned.

http://www.ootiz.com/m/ootiz_chat/?userid={member_id}

http://www.boonex.com/trac/dolphin/wiki/DolModMobile

I am extremely sorry that I am unable to implement the simple code. Apologies...............

Do I have to make some modification here in below file (ActivityBase.java)

    public void goToSo (View view) {

goToUrl ("http://ootiz.com/ootiz_chat/m/?userid=");    //Please help me here

    }

    private void goToUrl (String url) {

        Uri uriUrl = Uri.parse(url);

        Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uriUrl);

        startActivity(launchBrowser);

Refer to this doc:

http://www.boonex.com/trac/dolphin/wiki/DolModMobile

You need to insert record to sys_menu_mobile table. 

By Referring the doc , I tried to implement it in the android code but I am unable to use the {member id}

in the android app source code.

I think I am totally helpless at this point of time.

I tried different ways also search many techniques from searching in google.

Please provide me a simple way to insert the record  ::

You need to insert record to sys_menu_mobile table.

You don't need to modify code in Android app, you need to insert record to database only. It will add link to mobile app homepage or profile page. You can refer to existing records for an example.

If you can't insert a record - I can't help much - please hire someone to do it for you.